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  1. #include <stdio.h>
  2.  
  3. void cal(int x,int y,int *sum,int *diff,int *mul,int *mod) {
  4. 	*sum=x+y;
  5. 	if(x>y){
  6. 		*diff=x-y;
  7. 	}
  8. 	else{
  9. 		*diff=y-x;
  10. 	}
  11. 	*mul=x*y;
  12. 	if(y!=0){
  13. 		*mod=x/y;
  14. 	}
  15. }
  16.  
  17. int main(){
  18. 	int x,y;
  19. 	int sum,diff,mul,mod;
  20. 	scanf("%d %d",&x,&y);
  21. 	cal(x,y,&sum,&diff,&mul,&mod);
  22. 	printf("課題１\nx+y=%d\nx-y=%d\nx*y=%d\nx/y=%d",sum,diff,mul,mod);
  23. 	return 0;
  24. }
  25.  
  26.  
  27.  
Success #stdin #stdout 0.01s 5268KB
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4 2
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課題１
x+y=6
x-y=2
x*y=8
x/y=2
https://ideone.com/0niCSn
language:
C (gcc 8.3)
created:
12 days ago
visibility:
public

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