import java.util.Scanner;
class SubarrayCount {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
 
        long n = scanner.nextLong();
        long k = scanner.nextLong();
        long[] b = new long[(int)n];
 
        for (int i = 0; i < n; i++) {
            b[i] = scanner.nextLong();
        }
 
        long count = 0, sum = 0;
        int j = 0;
 
        for (int i = 0; i < n; i++) {
            // what if the entire arr has sum <k then j might increment infinitely or ot of bounds so j<n
            // move j so than sum is greater .. i.. j is valid .. then we need to find next i from which sum is valid.
            // shrink window by removing b[i] at end 
            while (j < n && sum < k) {
                sum += b[j];
                j++;
            }
            // if sum >= k, then all subarrays starting at i and ending from j-1 .. n-1 are valid
            if (sum >= k) {
                count += (n - j + 1);
            }
 
            sum -= b[i];  // move i forward (shrink window)
        }
 
        System.out.println(count);
        scanner.close();
    }
}
 

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