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  1. #include <stdio.h>
  2. #include <stdlib.h>
  3.  
  4. void bresenhamLine(int x1, int y1, int x2, int y2) {
  5.     int dx = x2 - x1;
  6.     int dy = y2 - y1;
  7.     int d = 2 * dy - dx;    // Initial decision parameter
  8.     int x = x1;
  9.     int y = y1;
  10.  
  11.     // Plot initial point
  12.     printf("Point: (%d, %d)\n", x, y);
  13.  
  14.     while (x < x2) {
  15.         x++;    // Move east
  16.  
  17.         if (d < 0) {
  18.             // Choose East pixel
  19.             d = d + 2 * dy;
  20.         } else {
  21.             // Choose Northeast pixel
  22.             y++;
  23.             d = d + 2 * (dy - dx);
  24.         }
  25.  
  26.         printf("Point: (%d, %d)\n", x, y);
  27.     }
  28. }
  29.  
  30. int main() {
  31.     int x1, y1, x2, y2;
  32.  
  33.     // Get input coordinates
  34.     printf("Enter starting point (x1 y1): ");
  35.     scanf("%d %d", &x1, &y1);
  36.  
  37.     printf("Enter ending point (x2 y2): ");
  38.     scanf("%d %d", &x2, &y2);
  39.  
  40.     // Draw the line
  41.     printf("\nPlotting line from (%d,%d) to (%d,%d)\n", x1, y1, x2, y2);
  42.     bresenhamLine(x1, y1, x2, y2);
  43.  
  44.     return 0;
  45. }
Success #stdin #stdout 0s 5296KB
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stdin
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Standard input is empty
stdout
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Enter starting point (x1 y1): Enter ending point (x2 y2): 
Plotting line from (1870463280,21947) to (511920176,32764)
Point: (1870463280, 21947)
https://ideone.com/39Pmew
language:
C++ (gcc 8.3)
created:
3 days ago
visibility:
public

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