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  1. #include <bits/stdc++.h>
  2. using namespace std;
  3.  
  4. int main() {
  5.     int n;
  6.     cin >> n;
  7.  
  8.     long long sum = n * (n+1)/2;  // مجموع 1..n
  9.     long long f = 1;
  10.  
  11.     while(f <= n) {
  12.         sum -= 2*f;  // نطرح ضعف كل قوة 2
  13.         f *= 2;        // القوة التالية
  14.     }
  15.  
  16.     cout << sum << endl;  // الناتج النهائي
  17. }
Success #stdin #stdout 0.01s 5316KB
comments (?)
stdin 
2
stdout 
-3
https://ideone.com/4YEkNj
language:
C++14 (gcc 8.3)
created:
2 days ago
visibility:
public

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