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  1. #include <stdio.h>
  2.  
  3. union Float64 {
  4. 	double y;
  5. 	char bytes[8];
  6. };
  7.  
  8. int main(void) {
  9. 	const char digits[] = "0123456789abcdef";
  10. 	union Float64 q;
  11.  
  12. 	printf("Test Case n=1\n");
  13.  
  14. 	q.y = 1;
  15. 	for (int i = 7; i >= 0; i--) {
  16. 		char a = digits[q.bytes[i] & 0x0f];         // lower nibble
  17. 		char b = digits[(q.bytes[i] & 0xf0) >> 4];  // upper nibble
  18. 		printf("%c%c ", b, a);
  19. 	}
  20. 	printf("(n)\n");
  21.  
  22. 	q.y = 2;
  23. 	for (int i = 7; i >= 0; i--) {
  24. 		char a = digits[q.bytes[i] & 0x0f];         // lower nibble
  25. 		char b = digits[(q.bytes[i] & 0xf0) >> 4];  // upper nibble
  26. 		printf("%c%c ", b, a);
  27. 	}
  28. 	printf("(n+1)\n");
  29.  
  30. 	q.y = 3;
  31. 	for (int i = 7; i >= 0; i--) {
  32. 		char a = digits[q.bytes[i] & 0x0f];         // lower nibble
  33. 		char b = digits[(q.bytes[i] & 0xf0) >> 4];  // upper nibble
  34. 		printf("%c%c ", b, a);
  35. 	}
  36. 	printf("(n+2)\n");
  37.  
  38. 	q.y = 4;
  39. 	for (int i = 7; i >= 0; i--) {
  40. 		char a = digits[q.bytes[i] & 0x0f];         // lower nibble
  41. 		char b = digits[(q.bytes[i] & 0xf0) >> 4];  // upper nibble
  42. 		printf("%c%c ", b, a);
  43. 	}
  44. 	printf("(n+3)\n");
  45.  
  46. 	q.y = 5;
  47. 	for (int i = 7; i >= 0; i--) {
  48. 		char a = digits[q.bytes[i] & 0x0f];         // lower nibble
  49. 		char b = digits[(q.bytes[i] & 0xf0) >> 4];  // upper nibble
  50. 		printf("%c%c ", b, a);
  51. 	}
  52. 	printf("(n+4)\n");
  53.  
  54. 	q.y = 6;
  55. 	for (int i = 7; i >= 0; i--) {
  56. 		char a = digits[q.bytes[i] & 0x0f];         // lower nibble
  57. 		char b = digits[(q.bytes[i] & 0xf0) >> 4];  // upper nibble
  58. 		printf("%c%c ", b, a);
  59. 	}
  60. 	printf("(n+5)\n");
  61.  
  62. 	q.y = 7;
  63. 	for (int i = 7; i >= 0; i--) {
  64. 		char a = digits[q.bytes[i] & 0x0f];         // lower nibble
  65. 		char b = digits[(q.bytes[i] & 0xf0) >> 4];  // upper nibble
  66. 		printf("%c%c ", b, a);
  67. 	}
  68. 	printf("(n+6)\n");
  69.  
  70. 	q.y = 8;
  71. 	for (int i = 7; i >= 0; i--) {
  72. 		char a = digits[q.bytes[i] & 0x0f];         // lower nibble
  73. 		char b = digits[(q.bytes[i] & 0xf0) >> 4];  // upper nibble
  74. 		printf("%c%c ", b, a);
  75. 	}
  76. 	printf("(n+7)\n");
  77.  
  78. 	q.y = 9;
  79. 	for (int i = 7; i >= 0; i--) {
  80. 		char a = digits[q.bytes[i] & 0x0f];         // lower nibble
  81. 		char b = digits[(q.bytes[i] & 0xf0) >> 4];  // upper nibble
  82. 		printf("%c%c ", b, a);
  83. 	}
  84. 	printf("(n+8)\n");
  85.  
  86. 	q.y = -1;
  87. 	for (int i = 7; i >= 0; i--) {
  88. 		char a = digits[q.bytes[i] & 0x0f];         // lower nibble
  89. 		char b = digits[(q.bytes[i] & 0xf0) >> 4];  // upper nibble
  90. 		printf("%c%c ", b, a);
  91. 	}
  92. 	printf("(-n)\n");
  93.  
  94. 	q.y = 0;
  95. 	for (int i = 7; i >= 0; i--) {
  96. 		char a = digits[q.bytes[i] & 0x0f];         // lower nibble
  97. 		char b = digits[(q.bytes[i] & 0xf0) >> 4];  // upper nibble
  98. 		printf("%c%c ", b, a);
  99. 	}
  100. 	printf("(n-1)\n");
  101.  
  102. 	q.y = -1;
  103. 	for (int i = 7; i >= 0; i--) {
  104. 		char a = digits[q.bytes[i] & 0x0f];         // lower nibble
  105. 		char b = digits[(q.bytes[i] & 0xf0) >> 4];  // upper nibble
  106. 		printf("%c%c ", b, a);
  107. 	}
  108. 	printf("(n-2)\n");
  109.  
  110. 	q.y = -2;
  111. 	for (int i = 7; i >= 0; i--) {
  112. 		char a = digits[q.bytes[i] & 0x0f];         // lower nibble
  113. 		char b = digits[(q.bytes[i] & 0xf0) >> 4];  // upper nibble
  114. 		printf("%c%c ", b, a);
  115. 	}
  116. 	printf("(n-3)\n");
  117.  
  118. 	q.y = -3;
  119. 	for (int i = 7; i >= 0; i--) {
  120. 		char a = digits[q.bytes[i] & 0x0f];         // lower nibble
  121. 		char b = digits[(q.bytes[i] & 0xf0) >> 4];  // upper nibble
  122. 		printf("%c%c ", b, a);
  123. 	}
  124. 	printf("(n-4)\n");
  125.  
  126. 	printf("End of Test");
  127.  
  128. 	return 0;
  129. }
Success #stdin #stdout 0s 5320KB
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stdin
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Standard input is empty
stdout
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Test Case n=1
3f f0 00 00 00 00 00 00 (n)
40 00 00 00 00 00 00 00 (n+1)
40 08 00 00 00 00 00 00 (n+2)
40 10 00 00 00 00 00 00 (n+3)
40 14 00 00 00 00 00 00 (n+4)
40 18 00 00 00 00 00 00 (n+5)
40 1c 00 00 00 00 00 00 (n+6)
40 20 00 00 00 00 00 00 (n+7)
40 22 00 00 00 00 00 00 (n+8)
bf f0 00 00 00 00 00 00 (-n)
00 00 00 00 00 00 00 00 (n-1)
bf f0 00 00 00 00 00 00 (n-2)
c0 00 00 00 00 00 00 00 (n-3)
c0 08 00 00 00 00 00 00 (n-4)
End of Test
https://ideone.com/4d0RvR
64-bit floating-point numbers, test case of 1
language:
C (gcc 8.3)
created:
1 day ago
visibility:
public

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