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  1. #include <stdio.h>
  2.  
  3. int isPalindrome(char s[]){
  4.     int i;
  5.     int n = 0;
  6.  
  7.     while (s[n] != '\0') {
  8.         n++;
  9.     }
  10.  
  11.     for (i = 0; i < n / 2; i++) {
  12.         if (s[i] != s[n - 1 - i]) {
  13.             return 0;
  14.         }
  15.     }
  16.  
  17.     return 1;
  18. }
  19.  
  20. int main(){
  21.     char s[100];
  22.     scanf("%s",s);
  23.     printf("%s -> %d\n",s,isPalindrome(s));
  24.     return 0;
  25. }
Success #stdin #stdout 0s 5304KB
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https://ideone.com/5iaUfh
language:
C (gcc 8.3)
created:
1 day ago
visibility:
public

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