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  1. #include <stdio.h>
  2.  
  3. int isPalindrome(char s[]){
  4. 	int i,n;
  5. 	for(i=0;s[i]!='\0';i++);
  6. 	n=i-1;
  7. 	for(i=0;s[i]==s[n-i];i++){
  8. 		if(s[i]=s[n-i]) return 1;
  9. 	}
  10. 	return 0;
  11. }
  12.  
  13. int main(void) {
  14. 	char s[100];
  15. 	scanf("%s",s);
  16. 	printf("%s -> %d",s,isPalindrome(s));
  17. 	return 0;
  18. }
Success #stdin #stdout 0.01s 5284KB
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stdin
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pap
stdout
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pap -> 1
https://ideone.com/7eoSmE
4/課題1-3/2回目
language:
C (gcc 8.3)
created:
5 days ago
visibility:
public

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