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  1. # include <stdio.h>
  2.  
  3. int isPalindrome(char s[]){
  4. 	char t[1024];
  5. 	int i;
  6. 	int count=0;
  7. 	//count
  8. 	for(count=0;s[count]!='\0';count++);
  9. 	//逆順
  10. 	for(i=0;i<count;i++){
  11. 		t[i]=s[count-i-1];
  12. 	}
  13. 	//comparing
  14. 	for(i=0;i<count;i++){
  15. 		if(s[i]!=t[i])return 0;
  16. 	}
  17. 	return 1;
  18. }
  19.  
  20. //メイン関数は書き換えなくてよいです
  21. int main(){
  22.     char s[100];
  23.     scanf("%s",s);
  24.     printf("%s -> %d\n",s,isPalindrome(s));
  25.     return 0;
  26. }
  27.  
Success #stdin #stdout 0s 5284KB
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https://ideone.com/A1Qg69
language:
C (gcc 8.3)
created:
1 day ago
visibility:
public

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