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  1. #include <stdio.h>
  2. #include <stdlib.h>
  3. #include <time.h>
  4.  
  5. void removefibas(int* arr, int* size, int index) {
  6.   if (index >= 0 && index < *size) {
  7.     for (int i = index; i < *size - 1; ++i) {
  8.       arr[i] = arr[i + 1];
  9.     }
  10.     (*size)--;
  11.   }
  12. }
  13.  
  14. int main() {
  15.   int n = 0, m = 0;
  16.   printf("enter long and width of the matrix: \n");
  17.   scanf("%d %d", &n, &m);
  18.   int** mat = malloc(sizeof(int*) * m);
  19.   for (int i = 0; i < n; i++) {
  20.     mat[i] = malloc(sizeof(int) * n);
  21.   }
  22.  
  23.   // Динамическое выделение памяти для массива fiba
  24.   int* fiba = malloc(sizeof(int) * 100); // Выделяем достаточно памяти
  25.   fiba[0] = 0;
  26.   fiba[1] = 1;
  27.   int fiba_count = 2;
  28.  
  29.   while (fiba[fiba_count - 1] < 320000) {
  30.     fiba[fiba_count] = fiba[fiba_count - 1] + fiba[fiba_count - 2];
  31.     fiba_count++;
  32.   }
  33.  
  34.   srand(time(NULL));
  35.  
  36.   int ran = 0;
  37.   fiba_count -= 1;
  38.  
  39.   for (int i = 0; i < n; i++) {
  40.     for (int j = 0; j < m; j++) {
  41.       ran = rand() % (fiba_count);
  42.       mat[i][j] = fiba[ran];
  43.       removefibas(fiba, &fiba_count, ran);
  44.       fiba_count--;
  45.     }
  46.     if (fiba_count < 0) {
  47.       printf("its too much numbers in matrix\n");
  48.       return 0;
  49.     }
  50.   }
  51.  
  52.   for (int i = 0; i < n; i++) {
  53.     for (int j = 0; j < m; j++) {
  54.       printf("%d ", mat[i][j]);
  55.     }
  56.     printf("\n");
  57.   }
  58.  
  59.   // Освобождаем память
  60.   free(fiba); // Освобождаем память для fiba
  61.   for (int i = 0; i < n; i++) {
  62.     free(mat[i]);
  63.   }
  64.   free(mat);
  65.  
  66.   return 0;
  67. }
  68.  
  69.  
Success #stdin #stdout 0.01s 5284KB
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3 4
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enter long and width of the matrix: 
10946 21 144 1 
4181 34 1597 610 
3 987 5 13
https://ideone.com/CFzo1n
language:
C (gcc 8.3)
created:
2 days ago
visibility:
public

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