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  1.  /* 1+0.1+3×2の計算結果を表示せよ*/
  2. #include <stdio.h>
  3. int main(void) {
  4.  double a;
  5.  a=1+0.1+3*2;
  6.  printf("%lf\n", a);
  7.  return (0);
  8. }
Success #stdin #stdout 0s 5284KB
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Standard input is empty
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7.100000
https://ideone.com/CrwW90
language:
C (gcc 8.3)
created:
7 days ago
visibility:
public

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