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  1. def is_leap_year(year):
  2.     if year <= 1582:
  3.         return "年份必须大于1582年"
  4.     if (year % 400 == 0) or (year % 100 != 0 and year % 4 == 0):
  5.         return f"{year}年是闰年"
  6.     else:
  7.         return f"{year}年不是闰年"
  8.  
  9. year = int(input())
  10. print(is_leap_year(year))
Success #stdin #stdout 0.12s 14084KB
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2020
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2020年是闰年
https://ideone.com/JjlhPQ
language:
Python 3 (python  3.12)
created:
8 hours ago
visibility:
public

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