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  1. # include <stdio.h>
  2.  
  3. int isPalindrome(char s[]){
  4.     int k;
  5.     int i;
  6.  
  7.     for(i=0;s[i]!='\0';i++){
  8.     }
  9.  
  10.     for(k=0;k<i/2;k++){
  11.         if(s[k]==s[i-1-k]){
  12.             continue;
  13.         }else{
  14.             return 0;
  15.         }
  16.     }
  17.  
  18.     return 1;
  19. }
  20.  
  21.  
  22.  
  23. int main(){
  24.     char s[100];
  25.     scanf("%s",s);
  26.     printf("%s -> %d\n",s,isPalindrome(s));
  27.     return 0;
  28. }
Success #stdin #stdout 0s 5288KB
comments (?)
stdin
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avavaa
stdout
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avavaa -> 0
https://ideone.com/LPBkyb
language:
C (gcc 8.3)
created:
1 day ago
visibility:
public

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