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  1. #include <stdio.h>
  2.  
  3. int kaijo(int x){
  4. 	int k;
  5. 	if(x==1){
  6. 		return 1;
  7. 	}
  8. 	else{
  9. 	k=x*kaijo(x-1);
  10. 	return k;
  11. 	}
  12. }
  13.  
  14. int main(void) {
  15. 	int n;
  16. 	scanf("%d", &n);
  17. 	kaijo(n);
  18. 	printf("%d! = %d", n, kaijo(n));
  19. 	return 0;
  20. }
  21.  
Success #stdin #stdout 0.01s 5320KB
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stdin
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10
stdout
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10! = 3628800
https://ideone.com/MM6J5W
1-0
language:
C (gcc 8.3)
created:
9 days ago
visibility:
public

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