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  1. #include <stdio.h>
  2. #include <ctype.h>
  3.  
  4. int main() {
  5.     int i;
  6.     float point, co_curricular, academic_merit, total_merit;
  7.     float total_points = 0.0;
  8.     char grade;
  9.  
  10.     // 显示评分表
  11.     printf("---------------------------------------\n");
  12.     printf("| Grade | A | B | C | D | E |\n");
  13.     printf("---------------------------------------\n");
  14.     printf("| Points| 4 | 3 | 2 | 1 | 0 |\n");
  15.     printf("---------------------------------------\n");
  16.  
  17.     // 输入四科成绩
  18.     for (i = 1; i <= 4; i++) {
  19.         printf("%d. Enter grade of the subject\t: ", i);
  20.         scanf(" %c", &grade);  // 跳过空白字符
  21.         grade = toupper(grade);  // 转大写
  22.  
  23.         switch (grade) {
  24.             case 'A': point = 4.00; break;
  25.             case 'B': point = 3.00; break;
  26.             case 'C': point = 2.00; break;
  27.             case 'D': point = 1.00; break;
  28.             case 'E': point = 0.00; break;
  29.             default:
  30.                 printf("Invalid grade entered.\n");
  31.                 return 1;  // 错误终止
  32.         }
  33.  
  34.         printf("Points obtain\t\t\t: %.2f\n", point);
  35.         total_points += point;
  36.     }
  37.  
  38.     // 输入并验证课外活动分
  39.     printf("\nEnter the co-curricular merit\n");
  40.     printf("Co-curricular merit\t\t: ");
  41.     fflush(stdout);  // 强制刷新输出缓冲区，确保提示显示
  42.     scanf("%f", &co_curricular);  // 输入值由终端自动回显在提示行
  43.  
  44.     if (co_curricular < 0 || co_curricular > 10) {
  45.         printf("Error: Co-curricular merit must be 0-10.\n");
  46.         return 1;
  47.     }
  48.  
  49.     // 计算与输出
  50.     academic_merit = total_points / 4;
  51.     total_merit = (academic_merit * 90) / 4 + co_curricular;
  52.  
  53.     printf("\nAcademic merit\t\t\t: %.2f\n", academic_merit);
  54.     printf("Total merit points\t\t: %.2f\n", total_merit);
  55.  
  56.     return 0;
  57. }
Success #stdin #stdout 0.01s 5288KB
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stdout
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---------------------------------------
| Grade | A | B | C | D | E |
---------------------------------------
| Points| 4 | 3 | 2 | 1 | 0 |
---------------------------------------
1. Enter grade of the subject	: Points obtain			: 4.00
2. Enter grade of the subject	: Points obtain			: 4.00
3. Enter grade of the subject	: Points obtain			: 4.00
4. Enter grade of the subject	: Points obtain			: 0.00

Enter the co-curricular merit
Co-curricular merit		: 
Academic merit			: 3.00
Total merit points		: 75.00
https://ideone.com/O6trDR
language:
C (gcc 8.3)
created:
7 days ago
visibility:
public

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