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  1. #include <iostream>
  2. #include <cmath>
  3.  
  4. using namespace std;
  5.  
  6. void input(double* a, int n) {
  7. 	for (int i = 0; i < n; i++)
  8. 		cin >> a[i];
  9. }
  10.  
  11. void output(double* a, int n) {
  12. 	for (int i = 0; i < n; i++)
  13. 		cout << a[i] << " ";
  14. }
  15.  
  16. double* sum(double* a, double* b, int n) {
  17. 	auto c = new double[n];
  18.  
  19. 	for (int i = 0; i < n; i++)
  20. 		c[i] = a[i] + b[i];
  21.  
  22. 	return c;
  23. }
  24.  
  25. double length(double* a, int n) {
  26. 	double sum = 0;
  27.  
  28. 	for (int i = 0; i < n; i++)
  29. 		sum += a[i] * a[i];
  30.  
  31. 	return sqrt(sum);
  32. }
  33.  
  34. double* normalize(double* a, int n) {
  35. 	auto normalized = new double[n];
  36.  
  37. 	double length_a = length(a, n);
  38.  
  39. 	for (int i = 0; i < n; i++)
  40. 		normalized[i] = a[i] / length_a;
  41.  
  42. 	return normalized;
  43. }
  44.  
  45. double dot(double* a, double* b, int n) {
  46. 	double sum = 0;
  47.  
  48. 	for (int i = 0; i < n; i++)
  49. 		sum += a[i] * b[i];
  50.  
  51. 	return sum;
  52. }
  53.  
  54. double distance(double* a, double* b, int n) {
  55. 	double sum = 0;
  56.  
  57. 	for (int i = 0; i < n; i++)
  58. 		sum += pow(b[i] - a[i], 2);
  59.  
  60. 	return sqrt(sum);
  61. }
  62.  
  63. double average(double* a, int n) {
  64. 	double sum = 0;
  65.  
  66. 	for (int i = 0; i < n; i++)
  67. 		sum += a[i];
  68.  
  69. 	return sum / n;
  70. }
  71.  
  72. int main() {
  73. 	int n;
  74. 	cin >> n;
  75.  
  76. 	auto a = new double[n];
  77.  
  78. 	input(a, n);
  79.  
  80. 	cout << average(a, n);
  81.  
  82. 	return 0;
  83. }
  84.  
Success #stdin #stdout 0s 5284KB
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https://ideone.com/Ow3TK4
language:
C++ (gcc 8.3)
created:
4 days ago
visibility:
public

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