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  1. #include <stdio.h>
  2.  
  3.  
  4. int main(void) 
  5. {
  6. 	double arr1[] = {5.2,9.3,6.5,4.1,7.8};
  7. 	double sum = 0;
  8. 	double average = 0;
  9.  
  10. 	for(int i = 0; i < 5; i++)
  11. 	{
  12. 		sum = sum + arr1[i];
  13. 		printf("arr1[%d] = %.2lf, sum = %.2lf\n",
  14. 				i, arr1[i], sum);
  15. 	}
  16. 		average = sum / 5;
  17. 		printf("average is: %.2lf\n", average);
  18.  
  19. 	return 0;
  20. }
Success #stdin #stdout 0s 5288KB
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stdin
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Standard input is empty
stdout
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arr1[0] = 5.20, sum = 5.20
arr1[1] = 9.30, sum = 14.50
arr1[2] = 6.50, sum = 21.00
arr1[3] = 4.10, sum = 25.10
arr1[4] = 7.80, sum = 32.90
average is: 6.58
https://ideone.com/Qqjntg
language:
C++ (gcc 8.3)
created:
2 hours ago
visibility:
public

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