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  1. # your code goes here
  2. n=int(input())
  3. freq=[0]*501
  4. for _ in range(n):
  5. 	y=int(input())
  6. 	freq[y]+=1
  7. minFreq=n+1
  8. maxFreq=0
  9. minElem=-1
  10. maxElem=-1
  11. for i in range(1,501):
  12. 	if freq[i]>0:
  13. 		if freq[i]<minFreq:
  14. 			minFreq=freq[i]
  15. 			minElem=i
  16. 		if freq[i]>maxFreq:
  17. 			maxFreq=freq[i]
  18. 			maxElem=i
  19. print(minElem, minFreq)
  20. print(maxElem, maxFreq)
Success #stdin #stdout 0.08s 14180KB
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https://ideone.com/SiRsiF
finding minimum and maximum frequency using the array range of 0-500
language:
Python 3 (python  3.12)
created:
2 hours ago
visibility:
public

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