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  1. #include <stdio.h>
  2.  
  3. void cal(int x, int y, int *sum, int *diff, int *mul, int *mod)
  4. 	{
  5.  
  6. 	*sum = x+y;
  7. 	if(x>y) {
  8. 		*diff = x-y;
  9. 	}
  10. 	else {
  11. 		*diff = y-x;
  12. 	}
  13. 	*mul = x*y;
  14. 	*mod = x/y;
  15.  
  16. 	}
  17.  
  18. int main(void) {
  19.  
  20. 	int x,y,sum,diff,mul,mod;
  21.  
  22. 	x=1;
  23. 	y=3;
  24.  
  25. 	cal(x,y,&sum,&diff,&mul,&mod);
  26.  
  27. 	printf("和は%d、差は%d、積は%d、商は%dである\n",sum,diff,mul,mod);
  28.  
  29. 	return 0;
  30. }
Success #stdin #stdout 0s 5288KB
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Standard input is empty
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和は4、差は2、積は3、商は0である
https://ideone.com/T4y57P
language:
C (gcc 8.3)
created:
1 day ago
visibility:
public

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