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  1. #include <stdio.h>
  2.  
  3. int isPalindrome(char s[]) {
  4. 	int ans = 1;
  5. 	int count = 0;
  6. 	while(s[count]!='\0') count++;
  7. 	int j = count-1;
  8.  
  9. 	for(int i=0; i<count/2; i++){
  10. 		if(s[i]!= s[j--]) return 0;
  11. 	}
  12. 	return 1;
  13. }
  14.  
  15. int main(){
  16. 	char s[100];
  17. 	scanf("%s",s);
  18. 	printf("%s -> %d\n",s, isPalindrome(s));
  19. 	return 0;
  20. }
  21.  
Success #stdin #stdout 0s 5284KB
comments (?)
stdin
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aiuia
stdout
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aiuia -> 1
https://ideone.com/VKUj3g
language:
C (gcc 8.3)
created:
5 days ago
visibility:
public

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