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  1. #include <stdio.h>
  2.  
  3. void cal(int x, int y, int *sum, int *diff, int *mul, int *mod) {
  4.     *sum = x + y;
  5.     *mul = x * y;
  6.     *mod = x % y;
  7.  
  8.     if (x - y < 0) {
  9.         *diff = -(x - y);
  10.     } else {
  11.         *diff = x - y;
  12.     }
  13. }
  14.  
  15. int main() {
  16.     int x, y, sum, diff, mul, mod;
  17.  
  18.     printf("xの値を入力してください: ");
  19.     scanf("%d", &x);
  20.     printf("yの値を入力してください: ");
  21.     scanf("%d", &y);
  22.  
  23.     cal(x, y, &sum, &diff, &mul, &mod);
  24.  
  25.     printf("x + y = %d\n", sum);
  26.     printf("x - y = %d\n", diff);
  27.     printf("x * y = %d\n", mul);
  28.     printf("x / y = %d\n", x / y);
  29.  
  30.     return 0;
  31. }
Success #stdin #stdout 0s 5280KB
comments (?)
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stdout
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xの値を入力してください: yの値を入力してください: x + y = 9
x - y = 1
x * y = 20
x / y = 0
https://ideone.com/fjTRWY
language:
C (gcc 8.3)
created:
1 day ago
visibility:
public

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