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  1. #include <stdio.h>
  2.  
  3. int main(void) {
  4.  
  5. 	int a,b,c,d,e,count=0;
  6.  
  7. 	scanf("%d %d %d",&a,&b,&c);
  8.  
  9. 	if(a<b){
  10. 	d=a;
  11. 	e=b;
  12. 	while(a<b){
  13. 	a++;
  14. 	if(c%a==0){
  15. 	count++;	}
  16. 	}
  17. 	}
  18. 	if(a>b){
  19. 	d=b;
  20. 	e=a;
  21. 	while(a>b){
  22. 	b++;
  23. 	if(c%b==0){
  24. 	count++;}
  25. 	}
  26. 	}
  27.  
  28. 	printf("%dから%dの範囲に%dの約数は%d個ある",d,e,c,count);
  29. 	return 0;
  30. }
  31.  
Success #stdin #stdout 0s 5296KB
comments (?)
stdin
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10 1 12
stdout
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1から10の範囲に12の約数は4個ある
https://ideone.com/oPIFMB
language:
C (gcc 8.3)
created:
1 day ago
visibility:
public

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