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  1. # include <stdio.h>
  2.  
  3. int isPalindrome(char s[]){
  4. 	int t[100];
  5. 	int count=0;
  6.  
  7. 		for(int i=0;s[i]!='\0';i++){
  8. 			count ++;
  9. }
  10.  
  11. 		for(int j=0;j<count;j++){
  12. 			t[j]=s[count-j-1];
  13. }
  14.  
  15. 		for(int k=0;s[k]==t[k];k++){
  16. 		if(s[k]=='\0') return 1;
  17. }
  18.  
  19. return 0;
  20.  
  21. }
  22. int main(){
  23.     char s[100];
  24.     scanf("%s",s);
  25.     printf("%s -> %d\n",s,isPalindrome(s));
  26.     return 0;
  27. }
Success #stdin #stdout 0s 5280KB
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https://ideone.com/xAy4Qs
language:
C (gcc 8.3)
created:
6 days ago
visibility:
public

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