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  1. #include <stdio.h>
  2.  
  3. void calc(int s, int t, int results[2]){
  4.     int i;
  5.     results[0] = 1;
  6.     results[1] = 1;
  7.  
  8.     for(i=0;i<s;i++){
  9.         results[0]*=3;
  10.     }
  11.  
  12.     for(i=0;i<t;i++){
  13.         results[1]*=3;
  14.     }
  15. }
  16.  
  17. int main(void){
  18.     int s, t;
  19.     int results[2];
  20.  
  21.     scanf("%d %d",&s,&t);
  22.  
  23.     calc(s,t,results);
  24.  
  25.     printf("3^%d=%d\n", s, results[0]);
  26.     printf("3^%d=%d\n", t, results[1]);
  27.  
  28.     return 0;
  29. }
Success #stdin #stdout 0.01s 5272KB
comments (?)
stdin 
3 6
stdout 
3^3=27
3^6=729
https://ideone.com/xdUOyB
language:
C (gcc 8.3)
created:
9 days ago
visibility:
public

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