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  1. import math
  2.  
  3. def allocate_students(schools, groups):
  4.   """
  5.   Allocates students from schools into groups, prioritizing the most even 
  6.   distribution possible.
  7.  
  8.   Args:
  9.     schools: A dictionary mapping school names to student counts.
  10.     groups: A list of group names.
  11.  
  12.   Returns:
  13.     A dictionary mapping school names to a list of (group, student_count) tuples.
  14.   """
  15.  
  16.   num_schools = len(schools)
  17.   num_groups = len(groups)
  18.   total_students = sum(schools.values())
  19.  
  20.   # Check if allocation is possible
  21.   if num_schools < 2 or num_groups < 2:
  22.     return None  # Not enough schools or groups
  23.  
  24.   # Calculate ideal group size
  25.   ideal_group_size = total_students // num_groups
  26.  
  27.   # Create the allocation dictionary (now with schools as keys)
  28.   allocation = {school: [] for school in schools}
  29.  
  30.   # Sort schools by student count in descending order
  31.   sorted_schools = sorted(schools.items(), key=lambda item: item[1], reverse=True)
  32.  
  33.   # Allocate students
  34.   group_counts = {group: 0 for group in groups}  # Track group sizes
  35.   for school, count in sorted_schools:
  36.     remaining_count = count
  37.     assigned_groups = 0
  38.     while remaining_count > 0:
  39.       # Find the group with the fewest students
  40.       min_group = min(group_counts, key=group_counts.get)
  41.  
  42.       # Calculate how many students to allocate to this group
  43.       allocate_count = min(remaining_count, ideal_group_size // 2)
  44.  
  45.  
  46.       allocation[school].append((min_group, allocate_count))
  47.       group_counts[min_group] += allocate_count
  48.       remaining_count -= allocate_count
  49.       assigned_groups += 1
  50.  
  51.     # Distribute remaining students one by one
  52.     while remaining_count > 0:
  53.       min_group = min(group_counts, key=group_counts.get)
  54.       allocation[school].append((min_group, 1))
  55.       group_counts[min_group] += 1
  56.       remaining_count -= 1
  57.  
  58.   return allocation
  59.  
  60. # Example usage
  61. schools = {
  62.     "kpu": 79,
  63.     "bij": 78,
  64.     "Mullahikheda": 39,
  65.     "SKP": 74,
  66.     "kamalpur": 34,
  67.     "Alinagar": 30
  68. }
  69. groups = ["Tushar red", "Adheep", "Valentina", "Kavita", "Manjari", "Surabhi", "Vishal", "Sukhmani", "planetarium"]
  70.  
  71. allocation = allocate_students(schools, groups)
  72.  
  73. if allocation:
  74.   for school, groups_and_counts in allocation.items():
  75.     print(f"{school}:")
  76.     for group, count in groups_and_counts:
  77.       print(f"  {group}: {count}")
  78. else:
  79.   print("Allocation not possible.")  # This should rarely happen
  80.  
  81.  
Success #stdin #stdout 0.04s 9668KB
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kpu:
  Tushar red: 18
  Adheep: 18
  Valentina: 18
  Kavita: 18
  Manjari: 7
bij:
  Surabhi: 18
  Vishal: 18
  Sukhmani: 18
  planetarium: 18
  Manjari: 6
Mullahikheda:
  Surabhi: 18
  Vishal: 18
  Sukhmani: 3
SKP:
  Manjari: 18
  Tushar red: 18
  Adheep: 18
  Valentina: 18
  Kavita: 2
kamalpur:
  planetarium: 18
  Kavita: 16
Alinagar:
  Sukhmani: 18
  Manjari: 12
https://ideone.com/zbyDdt
language:
Python 3 (python  3.9.5)
created:
7 days ago
visibility:
public

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